Enter in standard form the equation of the line passing through the given point and having the given slope.

b(2, - 5), m = -2/3

M = -2/3,   B(2, -5),   x₁ = 2, y₁ = -5

y - y₁ = m(x - x₁)

y - -5 = -(2/3)(x - 2)

3(y + 5) = -2(x - 2)

3y + 15 = -2x + 4

3y + 2x = 4 - 15

3y + 2x = -11