The angle of elevation from a viewer to the center of a fireworks display is 55°. If the viewer is 75 yards away from where the fireworks are launched, at what height is the center of the display? Round to the nearest whole yard

107.1075 yards

Step-by-step explanation:

To solve this problem, we can imagine a triangle, where one of the angles is 55 degrees, the adjacent cathetus is 75 yards, and we want to know the opposite cathetus (the height of the center of the display, "h").

The relation between opposite and adjacent cathetus is the tangent, so:

tan(55) = h/75

tan(55) = 1.4281, so:

h/75 = 1.4281

h = 75*1.4281 = 107.1075 yards

since proposition states that a number is greater than 25, if is true then the number must actually be greater than 25.

this implies that all possible options, except 24, can be accepted

i believe the answer is letter c) 8

step-by-step explanation: