Edmund fills his gas tank on Monday morning an then drives ten miles total for work each day of the work week. With a full tank of gas he can drive 100 miles. How many miles can he drive on the weekend, before he he fills up again?

50 miles.

Step-by-step explanation:

Edmund fills his gas tank on Monday morning an then drives ten miles total for work each day of the work week.

With a full tank of gas he can drive 100 miles.

Question asked:

How many miles can he drive on the weekend, before he he fills up again?

Solution:

With full tank he can drive a total distance = 100 miles

Each day of the work week, he drives = 10 miles

Total miles, he drive in whole work week (Monday - Friday) =

Now, to find that many miles he can drive on the weekend (Saturday and Sunday), we will subtract total miles, he drive in whole work week from the total distance, he can drive with full tank of gas:-

100 - 50 = 50 miles.

Therefore, he can drive 50 miles on the weekend, before he he fills up again.

choice b is correct

step-by-step explanation:

we have been given the following system of inequalities;

we are required to graph the solution to the system of inequalities. using a graphing tool, the graph of the system is as shown in the attachment. the continuous line represents the graph of while the dotted line represents .

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.