What is the 30th term of the linear sequence below?

-5,-7,-9,-11,-13

The 30th term of the given linear sequence is -63 and this can be determined by using the nth term formula of the arithmetic operation.

Given :

Sequence ---  -5,-7,-9,-11,-13,...

The given sequence is in arithmetic progression whose difference is given by:

-7 - (-5) = d

d = -2

The nth term in the arithmetic progression is given by the formula:

where 'n' is the number of terms, 'a' is the first term, is the nth term, and 'd' is the difference.

Now, substitute the known terms in the above formula.

So, the 30th term of the given linear sequence is -63.

For more information, refer to the link given below:

link

-63

Step-by-step explanation:

This arithmetic progression

The formula is a+(n-1)d

a means the first value

n is the nth term

d is the difference

So a is -5

n is 30

d is -2

So let's substitute

-5+(30-1)-2

-5+(29)-2

-5-58

-63

Therefore the final answer is-63

Just follow the step and the general formula, you will get your final answer

a

step-by-step explanation:

when a number is between two straight lines it means the absolute value.

to find absolute value you need to know how many numbers is that number away from 0.

when finding absolute value the number will always come out positive

so absolute value of -3 is 3

absolute value of 3/2 is 3/2

absolute value of -2 is 2

absolute value of 3.5 is 3.5

absolute value of -1 is 1

now put these numbers in order:

a)   |-1|, |3/2|, |-2|, |-3|, |3.5|

i get you, what you should do is think of the positive things that would come out of it. it will make yours parents proud and raise your grade. you should always try and if you can't focus tell the teacher.