Assume that the arrival of airplanes at a one-runway airport is a Poisson distribution with a mean rate of 8 planes per hour. The landing time (service time, not service rate which would be planes/min) is an exponential distribution with a mean of 5 minutes per plane. What is the mean number of planes in a holding (planes circling around waiting to land) pattern (compute exact number)? a. 1 b. 1.33 c. 2 d. 1.67

Option b that is 1.33 is the right choice.

Step-by-step explanation:

Given:

Mean rate of arrival = 8 planes/hr

Service time = minute/plane

Mean service rate   = = planes/hr

Applying the concept Poisson-distributed arrival and service rates (exponential inter-arrival and service times)(M/M/1) process:

We have to find mean number of planes waiting to land that is mean number of customers in the queue .

Mean number of customers in queue .

⇒

   Considering, , is also mean number of customers in service.

⇒

⇒ Plugging the values.

⇒

⇒

⇒

So,

Mean number of planes in holding and waiting to land = 1.33

your answer would be 40

step-by-step explanation:

constant acceleration- a

constant velocity- c

no velocity or acceleration- b

explanation:

for body moving with a constant acceleration, the rate of change of displacement changes over time. this is proven by the increasing gradient of the curve (a) against time.

a body that is moving at constant velocity covers equal distances over equal periods of time, thus the straight line with a constant gradient c.

a stationary body   covers no displacement as time elapses. thus the flat line with   zero gradient.