Given m∠LON\qquad m \angle LON m∠LON m, angle, L, O, N is a straight angle. m∠LOM=4x+30∘\qquad m \angle LOM = 4x + 30^\circ m∠LOM=4x+30 ∘ m, angle, L, O, M, equals, 4, x, plus, 30, degrees m∠MON=8x+90∘\qquad m \angle MON = 8x + 90^\circ m∠MON=8x+90 ∘ m, angle, M, O, N, equals, 8, x, plus, 90, degrees Find m∠MONm\angle MON m∠MON m, angle, M, O, N : OO O LL L NN N MM M ∘{}^{\circ} ∘ degrees Show Calculator Stuck?Watch a video or use a hint. Report a problem

definition: a circle is the  set of all points in a plane that are equidistant  from a given  point  called the center of the circle. we use the symbol ⊙ to represent a circle. the a line segment from the center of the circle to  any point  on the circle is a radius of the circle.

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i googled it and this is what i got i don't know how it is. sorry.

the square root of what number? if you add that, then someone will probably answer the question.

kbmflmklbhml; bmlzb; bdhzz

step-by-step explanation: