Find all solutions in the interval from [0,2pi)
2cos(3x)= -sqrt{2}

Solutions of in the interval from [0,2pi) is  and .

Step-by-step explanation:

Find all solutions in the interval from [0,2pi)

⇒

⇒

⇒

⇒

⇒

⇒

⇒

⇒

Cosine General solution is :

⇒ , k is any integer .

At k=0,

⇒ ,

At k=1,

⇒

⇒

Therefore , Solutions of in the interval from [0,2pi) is  and .

a

step-by-step explanation:

1) the property is   ixi = a ⇔x = a   o x = -a

4(x-5)+3= 15⇒4x-20+3 = 15⇒4x-17= 15⇒4x = 15+17⇒4x = 32⇒x =32/4= 8

4(x-5) +3= -15⇒4x-20 +3 = -15⇒4x-17= -15⇒4x =-15+17⇒4x = 2⇒x =2/4= 1/2

the values are x =8 and x = 0,5