Determine the discriminant of x2 = 4.

a. 17
b. 16
c. -15
d. -10

The discriminant is b²-4ac
We can rewrite x² = 4 to x² + 0x - 4 = 0
So a = 1, b = 0, c = -4
Δ = 0 - 4 * 1 * -4
Δ = 16
The answer is B

X² = 4

x² - 4 = 0   comparing to  ax² + bx + c = 0,   a = 1, b = 0, c = -4

Discriminant = b² - 4ac

b² - 4ac = 0² - 4*1*-4 = 0 + 16 = 16

Discriminant = 16.

option B 

The decimal expansion would be .27 repeated