1. if ƒ (x ) = 2x^2 + 3, find ƒ (3).

2. simplify.
(x 3)^4 • x^-3

3. simplify.
8 - 3(4 - 2x )

4.
if ƒ (x ) = 4x - 3, what is ƒ (x )^-1?

5.
if ƒ = {(2, 5), (3, 2) (4, 6), (5, 1), (7, 2)}, then ƒ is a function.

f = {(2, 5), (3, 2) (4, 6), (5, 1), (7, 2)} is a function

Step-by-step explanation:

we have to find the value of f(3)

Substitute x=3

we have to simplify the above expression

we have to find the

Replace f(x) to y

To find inverse we have to replace x=y and y=x, we get

Now solve for y and replace y with

which is required inverse

we have to find f is function or not.

If one element of domain x has unique image in range i.e in Y set then only f is called function.

Here one maps to unique element

Therefore f is function.