On a coordinate plane, a line goes through (0, 3) and (3, negative 1). A point is at (negative 3, 2). What is the equation of the line that is parallel to the given line and passes through the point (−3, 2)? 3x − 4y = −17 3x − 4y = −20 4x + 3y = −2 4x + 3y = −6

(6,1)(5,4)slope = (4 - 1) / (5 - 6) = 3/-1 = -3y = mx + bslope(m) = -3use either of ur , = 6 and y = 1now sub and find b, the y int1 = -3(6) + b1 = -18 + b1 + 18 = b19 = bso ur equation is : y = -3x + we need it in standard formy = -3x + 3x to both sides3x + y = 19 < == standard form

A67 it might be it or c 67