Investment a has a value of $50 at the end of the first year and increases by 8% every year. Investment b has a value of 60$ at the end of the first year and increases by $3 every year. What's the first year investment a

a's initial amount before investment= $42.296296

Step-by-step explanation:

After first year investment of a became $50 because of increase of 8%

Hence initial invest is simply 100% because $50 is 108%

Hence using direct proportion

108% is $50, Hence 100% will be = (100 x 50) / 108 = $42.296296

its 69.420

step-by-step explanation:

hello from mrbilldoesmath!

answer:   x (x+6)^2, choice b

discussion:

factor x out of the equation:

x^3 + 12x^2 + 36x = x (x^2 + 12x + 36).

note that 6+6 = 12 and 6*6 = 36 so the above factors into:

x (x+6)^2

which is choice b

you,

mrb