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Mathematics, 23.03.2020 20:38 heybrothwrlogan

The rectangle below has an area of 15k^4+35k^3+20k^215k
4
+35k
3
+20k
2
15, k, start superscript, 4, end superscript, plus, 35, k, cubed, plus, 20, k, squared.
The width of the rectangle is equal to the greatest common monomial factor of 15k^4, 35k^3,15k
4
,35k
3
,15, k, start superscript, 4, end superscript, comma, 35, k, cubed, comma and 20k^220k
2
20, k, squared.
What is the length and width of the rectangle?

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Answers: 2

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You know the right answer?
The rectangle below has an area of 15k^4+35k^3+20k^215k
4
+35k
3
+20k
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