What is the equation for the circle with the center (11,6) and passes through the point (17,12)

A)(x-11)^2+(y+6)^2=36
B)(x-11)^2+(y-6)^2=36
C)(x+6)^2+(y-6)^2=72
D)(x-11)^2+(y-6)^2=72

The answer to your question is the letter D. (x - 11)² + (y - 6)² = 72

Step-by-step explanation:

Data

Equation = ?

Center = (11, 6)

Point = (17, 12)

Process

1.- Calculate the length of the radius using the distance between two points formula.

d =

x1 = 11    y1 = 6

x2 = 17  y2 = 12

-Substitution

d =

d =

d =

d =

radius =

2.- Write the equation of the formula

    (x - 11)² + (y - 6)² = ()²

Result

   (x - 11)² + (y - 6)² = 72

it is contrapositive

i could not see the question too well so check yourself again too . this is because i want you to get it correct.