What is the slope of the line that contains the points (-3, 5) and (-5, 6)?

Slope m=-1/2

Step-by-step explanation:

The slope is m=dy/dx=(y2-y1)/(x2-x1), where index 1 refers to the first point (-3,5). The index 2 refers to the second point (-5,6).

We get:

m=(6-5)/((-5)-(-3))=1/(-5+3)=-1/2

- 1/2

Step-by-step explanation:

Slope = y2- y1/x2 - x1

Given

x1 = -3

y1 = 5

x2 = -5

y2 = 6

Therefore

Slope = 6 - 5 /-5 -(-3)

= 6-5/-5+3

= 1/-2

= - 1/2

answer

see attachment

explanation

the given function is

this function has y-intercept at

-4 and a slope of 2.

note that, the graph has a positive slope.

the graph that represents this function is the straight line that moves upward from left to right.

the graph touches the y-axis at -4.

the correct choice is the graph shown in the attachment.

idk

step-by-step explanation: