An electrical rm manufactures light bulbs that have a life span that is approximately normally distributed. The population standard deviation is not known. A sample of 30 bulbs are found to have an average life span of 800 hours and a sample standard deviation of 45 hours. Test the hypothesis that µ = 800 against the alternative µ ≠ 800 if a random sample of 30 bulbs has an average life 788 hours. Use P value in your answer.

The 't' test statistic = 1.46 < 1.69

The test of hypothesis is H 0 :μ = 800 is accepted

A sample of 30 bulbs are found came from average µ= 800

Step-by-step explanation:

Step 1:-

Given population of mean μ = 800

given size of small sample n =30

sample standard deviation 'S' = 45

Mean value of the sample χ = 788

Null hypothesis µ  =800

alternative hypothesis   µ ≠ 800

Step 2:-

The 't' test statistic t =  

                       t = = 1.4607

Step 3:-

The degrees of freedom γ = n-1 = 30-1 =29

From "t" value from table at 0.05 level of significance ( t = 1.69)

The calculated value t = 1.4607 < 1.69

Therefore The null hypothesis H_{0} ' is accepted.

conclusion:-

A sample of 30 bulbs are came found from average µ= 800

10000

step-by-step explanation: divide by 2,

60.9774

step-by-step explanation:

because when you add 47.6 plus 7.32 equals 54.92

and when you add .0574 + 6= 6.0574

and when you add 54.92 and 6.0574 you get the answer of 60.9774.

plzz mark brainlest last one got deleted. cause i didn't explain it but i did but i understand what the mod meant