Absorption rates into the body are important considerations when manufacturing a generic version of a brand-name drug. A pharmacist read that the absorption rate into the body of a new generic drug (G) is the same as its brand-name counterpart (B). She has a researcher friend of hers run a small experiment to determine if the mean adsorptions rates are different. The experiment had 17 participants in each group (generic vs. brand-name). The p-value for the test was 0.0700. Use this information to answer the following questions.

A. Deciding that the absorption rates are the same, when in fact they are.

B. Deciding that the absorption rates are different, when in fact they are.

C. Deciding that the absorption rates are the same, when in fact they are not.

D. Deciding that the absorption rates are different, when in fact they are not.

E. The researcher cannot make a Type I error, since he has run an experiment.

Type I error is nothing but Reject the H0 when H0 is true.

Here H0:  the absorption rates are the same

H1:  the absorption rates are different

Now Type I err or is Deciding that the absorption rates are different, when in fact they are

step-by-step explanation:

1. sometimes

2.   never

3   .08c = 7.50+.05c   250 pages

step-by-step explanation:

1.   sometimes

the theoretical probability of rolling a 1 is 1/6.   perhaps you got really lucky and never rolled a 1   in those 60 times.   your experimental probability is 0.   or perhaps you rolled a 1   20 times.   your experimental probability is 20/60 is 1/3.     it really just depends on how you rolled in that experiment.

2.   never

the probability of the event occurring is 1.   that is being 100 % sure it will happen.   that is the maximum amount of confidence we have.

3.   no customer card cost:   .08 times number of pages

customer card cost:   7.50 + .05 times number of pages

we want to find when it costs the same amount, so we will set these equal

let c = number of pages

.08c = 7.50+.05c

subtract .05c from each side

.08c-.05c = 7.5+.05c-.05c

.03c=7.5

divide each side by .03

.03c/.03 = 7.5/03

c =250  

the cost is the same at 250 pages