Over the course of a multi-stage 4510-km bicycle race, the front wheel of an athlete's bicycle makes 1.70x106 revolutions. How many revolutions would the wheel have made during the race if its radius had been 1.3 cm larger

The wheel have made revolutions.

Step-by-step explanation:

The total distance traveled during the race is

D = 4510km [(1000m)/(1km)] =

The radius (r1) of the smaller bicycle wheel is

r1 =

Than the larger wheel has a radius

r2 = 0.329 m + 0.012 m = 0.341 m

Over the same distance this wheel would make N2 revolutions

N2 =

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

the rocket cannot penetrate the ground, in a contextual sense, therefore the roots of this equation should be the domain of this function. i'll let you find the roots of this quadratic equation (hint: use the quadratic formula:  

1- c

2-a

step-by-step explanation:

mark brainliest!