A man just bought suits, shirts, and ties. All of these suits, shirts, and ties coordinate with each other. If he is to randomly select one suit, one shirt, and one tie to wear on a certain day, how many different outcomes (selections) are possible? outcomes

He can make a total of x*y*z selections, where x is the amount of suits he bought, y the amount of shirts he bought and z the amount of ties he bought.

Step-by-step explanation:

You probably forgot to mention how many of each kind did he buy.

Let x mean the amount of suits he bought, y the amount of shirts and z the amount of ties. The total amount of combinations that man can make can be computed by multiplying x, y and z: for each of the x suits, he can select y shirts, thus he has x*y possibilities to select one shirt and one suit. For each pair of suit and shirt (there are xy in total), he has z possibilities to select a tie, giving us a total of xy*z = xyz ways to select one suit, one shirt and one tie.

answer: on graphs, the open and closed circles, or vertical asymptotes drawn as dashed lines us identify discontinuities.

as before, graphs and tables allow us to estimate at best.

when working with formulas, getting zero in the denominator indicates a point of discontinuity.

when working with piecewise-defined functions, check for discontinuities at the transition points where one piece ends and the next begins.

step-by-step explanation: