Idk if you guys will do this or if i'm asking to much, if you guys could help me do this, thank you, if not its okay.

You only need three formulas:

Area of a rectangle = length * width

Remember that a square is a rectangle for which length = width, so its area would be length^2.

Area of a circle = π * radius^2

The diameter of a circle is twice the radius, so radius = diameter/2, so the area can also be written as π * (diameter/2)^2

Area of a triangle = 1/2 * length * width

For a right triangle, the length and width correspond to the shortest two legs. For the non-right triangles shown here, the use the height of the triangle (dashed lines) and the bases that run perpendicular to them.

Some examples: (taken from the even-numbered pool)

2. The radius of the circle is 7 in, so the area is π * (7 in)^2 = 49π in^2.

6. This is a right triangle; its legs have lengths 15 mm and 20 mm, so its area is 1/2 * (15 mm) * (20 mm) = 150 mm^2.

8. The triangle has height 24 m and area 120 m^2. So the base has length b such that

120 = 1/2 * (24 m) * b

and solving gives b = 10 m.

12. The circle has area 200.96 cm^2, so the diameter d is such that

200.96 cm^2 = π * (d/2)^2

This gives (approximately, using π = 3.14)

64 cm^2 = (d/2)^2

8 cm = d/2

d = 16 cm

what?

step-by-step explanation:

there is no question content here, but you for the free points! : d