In an examination, Adenike obtained 19marks more than musa. if adenike had obtained one and half times her own mark, she would have score 6 marks more than twice musa mark. find the mark score by each of them.

Adenike scored 64 marks, while Musa scored 45 marks

Step-by-step explanation: We shall start by assigning letters to each unknown variable. Let Adenike’s mark be d while Musa’s mark shall be m.

First of all, if Adenike obtained 19 marks more than Musa, then if Musa scored m, Adenike would score 19 + m (or d = 19 + m). Also if Adenike has obtained one and half her own mark (which would be 1 1/2d or 3d/2), it would have been equal to 6 times more than twice Musa’s mark (or 6 + 2m). This can be expressed as

3d/2 = 6 + 2m. So we now have a pair of simultaneous equations;

d = 19 + m ———(1)

3d/2 = 6 + 2m ———(2)

Substitute for the value of d into equation (2), if d = 19 + m

(3{19 + m})/2 = 6 + 2m

By cross multiplication we now have

3(19 + m) = 2(6 + 2m)

57 + 3m = 12 + 4m

We collect like terms and we have

57 - 12 = 4m - 3m

45 = m

We now substitute for the value of m into equation (1)

d = 19 + m

d = 19 + 45

d = 64

So Adenike scored 64 marks while Musa scored 45 marks

step-by-step explanation:

if you want to solve percent error follow these steps.

1. subtract the accepted value from the experimental value.

2. take the absolute value of step 1.

3. divide that answer by the accepted value.

4. multiply that answer by 100 and add the % symbol to express the answer as a percentage.

if you want to solve percent of change just do this.

1. work out the difference (increase) between the two numbers you are comparing.

2. divide the increase by the original number and multiply the answer by 100. if your answer is a negative number then this is a percentage decrease.

hope this : )

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step-by-step explanation: