What is the first step when rewriting y = –4x2 + 2x – 7 in the form y = a(x – h)2 + k? . 2 must be factored from 2x – 7. –4 must be factored from –4x2 + 2x. x must be factored from –4x2 + 2x. –4 must be factored from –4x2 – 7

Hello qualityguard, please ask for correction next time

basically, complete the squaer

for y=ax²+bx+c
a is the quadratic coefient
b=linear coefient

steps
1. group x terms

2. factor our quadratic coefient

3. take 1/2 of the linear coefient and square it

4. add negative and positive of it insides parentahes

5. factor perfect squaer trinomial

6. expand

so

y=-4x²+2x-7

first step is group x terms
y=(-4x²+2x)-7
hmm, not listed

next step is to factor -4 from -4x²+2x
y=-4(x²+0.5x)-7
yep

answer is to factor -4 from -4x²+2x

The correct answer is –4 must be factored from –4x2 + 2x. This is due to -4 needing to be separated from the common numeral in the equation which is 2.