A new surgery is successful 85% of the time. If the results of 6 such surgeries are randomly sampled, what is the probability that fewer than 4 of them are successful

The probability that fewer than 4 of them are successful are 0.9527

Explanation:

Given:

number of trials, n = 6

p(successful) = 0.85

P(x >= 4) = ?

The problem can be solved using binomial probability formula.

 P(x >= 4) = 1 - binomcdf(6,0.85,4) = 1 - 0.0473

               = 0.9527

Therefore, the probability that fewer than 4 of them are successful are 0.9527

on a coordinate grid, point a is at (−4.0, −2.4) and point b is at (4.0, −2.4). point b is a reflection of point a across the –axis. input either a lowercase x or i think is the right awnser

step-by-step explanation:

both graphs increase on their domain

neither graph has a y-intercept

step-by-step explanation:

the following points can be visualized easily from the graph