There is a three digit number. The second digit is four times as big as the third digit, while the first digit is three less than the second digit. What is the number?

141 and 582

Step-by-step explanation:

x,y,z are all single digit integers.

y = 4z - in order to be single digit, z must equal 0,1, or 2.

x = y-3 - since y is a single digit, the greatest x can be is 6 (when y is equal to 9). Assuming Y also has to be greater than three because x cannot be negative or equal to zero.

Based on this assumption, y cannot equal zero therefore z cannot equal zero.

If z=1, y=4, and x=1 making 141 a solution.

If z=2, y=8, and x=5 making 582 a solution.

i would have to say it is c.