URGENT ASAP:
What is the area of the irregular pentagon?
A. 43 inches squared
B. 105 inches squared
C. 108 inches squares
D. 114 inches squared

The correct answer is option B; 105 inches squared

Step-by-step explanation: Please refer to the attached diagram for details.

The irregular pentagon with five sides has been separated into two regular shapes in order to ease our calculations. Observe carefully and you’ll discover that it consists of a triangle and rectangle combined together.

You now have triangle ABF and rectangle FCDE. Line FC and line ED in the rectangle measure 12 inches while the width line FE and line CD measure 8 inches. Area of the rectangle is calculated as,

Area = L x W

Area = 12 x 8

Area = 96 square inches

Looking at the triangle, the vertical height is 6 inches, that is length 14 minus length 8 taken out of the rectangle. Also the base is 3 inches, that is length 12 minus length 9 (where the triangle is cut out of the irregular polygon). With the height and the base now known, the area of the triangle is calculated as,

Area = 1/2 x (Base x Height)

Area = 1/2 x (3 x 6)

Area = 1/2 x 18

Area = 9 square inches

The area of both parts of the irregular shape added together gives the answer to the question

Area of the irregular pentagon = 96 + 9

Area = 105 inches squared

x= -3

step-by-step explanation:

step 1: simplify brackets

4 - x - 1 = 6

step 2: simpilfy

3 - x = 6

step 3: subtract 3 from both sides

-x = 6 - 3

step 4: simpilfy 6 - 3

-x = 3

step 5: multiply both sides by -1

x = -3

step-by-step explanation:

here's what happens:

1) the graph of f   = x^2 is shifted 2 units to the right.

2) the resulting graph is reflected in the x-axis, so that the parabola now opens down.

3) this final result is transformed up by 5 units.