Tony hit a baseball into the air with an initial upward velocity of 48 ft per second. H=height in feet.

The height of the baseball going upwards is 35.77 ft

Explanation:

Given:

initial velocity, u = 48 ft/s

Height, h = ?

If the ball is thrown in the air, then the final velocity of the ball will be 0 as the ball later comes to rest.

Acceleration of the ball will be acceleration due to gravity

g = 9.8 m/s²

g = 32.2 ft/s²

We know,

(v)² - (u)² = 2gh

(0)² - (48)² = 2 X 32.2 X h

2304 = 64.4 X h

Therefore, height of the baseball going upwards is 35.77 ft

expression #3 is not equivalent. the others are.

your answer is b ^w^ hope i