Two cyclist leave towns 78 miles apart at the same time and travel toward each other. One cyclist travels 5 mi/h faster than the other. If they meet in 2 hours, what is the rate of each cyclist ?

One cyclist travels at 17 m/h and the other at 22 m/h.

Step-by-step explanation:

Let one cyclist travel at x m/h and the other at (x+5) m/h.

Their combined speed is x + x + 5 = 2x+5 m/h.

When they meet the total distance they have travelled will be 78 miles.

Speed = distance / time taken, so:

2x+5 = 78/2

2x + 5 = 39

2x = 34

x = 17 m/h = speed of one cyclist.

So the other travels at 17+5 = 22 m/h.

a² + b²= c²

24² + 7² = c²

c= 25