A $9,000 principal is invested in two accounts, one earning 7% interest and another earning 9% interest. If the total interest for the year is $782, then how much is invested in each account?

The amount invested at 7% is $1,400 and the  amount invested at 9% is $7,600

Step-by-step explanation:

Let

x ----> amount invested at 7%

(9,000-x) -----> amount invested at 9%

we know that

The interest earned by the amount invested at 7% plus the interest earned by the amount invested at 9% must be equal to $782

so

The linear equation that represent this problem is

solve for x

therefore

The amount invested at 7% is $1,400 and the  amount invested at 9% is $7,600

step-by-step explanation: