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A box contains 11 marbles—7 red and 4 green.
Five of these marbles are removed at random.
If the probability of drawing a green marble is
now 0.5, how many red marbles were removed
from the box?

4 red marbles were removed  from the box .

Step-by-step explanation:

Here we have , A box contains 11 marbles—7 red and 4 green.  Five of these marbles are removed at random.  If the probability of drawing a green marble is  now 0.5, We need to find  how many red marbles were removed  from the box .Let's find out:

Let number of green marbles removed be x , According to question , after removing 5 marbles we now have , marbles ,So probability of drawing a green marble is  now 0.5 i.e.

⇒

⇒

⇒

So , Number of green marbles left is 3 after removal of 5 marbles from box that means only 1 green marble is removed and , 4 red marbles are removed .

Therefore , 4 red marbles were removed  from the box .

it is a. 4.2 because 7.6-3.4 gets the remaining length of 4.2. i might be wrong but i am pretty sure this is the answer.

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°