Derek rolls a die many times and records the number of times he rolls a three. Arrange the following situations in order from the situation that
gives the largest difference between relative frequency and actual probability to the situation that gives the smallest difference
Derek rolls the
die 10 times
Derek rolls the
die 30 times
Derek rolls the
die 5 times.
Derek rolls the
die 20 times

There is NO situation that  gives the largest difference between relative frequency and actual probability to the situation that gives the smallest difference.

Step-by-step explanation:

Event (E) = Denotes getting 3 when rolling a single die.

Here first we find the probability of not getting a 3 from rolling a die

The probability of the event (E) is P(E) =(1/6)  

(No. of favorable outcome/Total no. of possible outcomes).

The probability of not getting 3 is 1-P(E)=1–(1/6)=(5/6). =0.8333

1.Times of rolling a dice  =  10 times

Relative frequency          =   1/6 ^10 = 1.67

Actual probability            =  1 - (5/6)^10. = 1.67

Result                                = No difference

2.Times of rolling a dice  =  30 times  

Relative frequency          =   1/6 ^30 = 5

Actual probability            =  1 - (5/6)^30. = 5

Result                                = No difference

3. Times of rolling a dice  =  5times

Relative frequency          =   1/6 ^5 = 0.835

Actual probability            =  1 - (5/6)^5. = 0.835

Result                                = No difference  

4. Times of rolling a dice  =  20times

Relative frequency          =   1/6 ^20 =  3.341

Actual probability            =  1 - (5/6)^20. = 3.341

Result                                =  No difference  

here the times of rolling a dice were different but the dice been a single one having only 6 out comes .,so the outcomes of both relative frequency and actual probability is same in all the cases.,

The sentence sequence is "BDAC".

Step-by-step explanation:

yo answer should be 6 if im not mistaken

step-by-step explanation: