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The table shows all the possible outcomes for spinning the pointer of a spinner with four equal-sized sections labeled 1-4 and another spinner
with four equal-sized sechons labeled A-D. What is the probability that the two pointers will land on an odd number and the letter C? Give the
probability as a percent. Enter your answer in the box
1 1.A 1.B 1.C 1.D
1 2.A 2.B 2. C 2.D
3 3.A 3.B 3.C 3.D
P(odd number, C) = ( %)

12.5%

Step-by-step explanation:

There are two types of spinners here and the outcome of them is independent. That means

P(odd number,C) = P(odd number) * P(C)

There are two odd numbers out of four numbers in the first spinner. The chance of odd number will be:

P(odd) = 2/(2+2)= 1/2= 50%

There are four letters and the desired outcome is C. The chance for C will be:

P(C)= 1/4= 25%

Then the chance will be:

P(odd number,C) = P(odd number) * P(C)

P(odd number,C) =50% * 25% = 12.5%

3/4 ÷ 3/4

step-by-step explanation:

basically divide any proper fraction with itself to fit the criteria.

so if we are using 3/4, then:

3/4 ÷ 3/4 = 1

so 1 is the quotient.

and the numerators for both these fractions is 3.   and if we divide the numerators:

3 ÷ 3 = 1

we see that quotient is equal to our original quotient as well.

if you explain the the question more correctly i might be able to answer this better

step-by-step explanation: