A number m is such that when it is divided by 30,36 and 45 ,the remainder is always 7.Find the smallest possible value of m

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Step-by-step explanation:

Suppose that you are looking for b, instead of the irrelevant value of m

The statements of this problem suggest us to look for the Least Common Multiple (LCM) of 30, 36 and 45

The number b will be that LCM + 7.

Hence,

30 = 2 x 3 x 5

36 = 2^2 x 3^2

45 = 3^2 x 5

LCM = 180

Therefore the smallest possible value of b (or ‘m’ as per question) is -> LCM+7 that is 180+7= 187

a. the are of the rectangle is 18.25

b. 18.25 times two is 36.50

rae me : d

see explanation

step-by-step explanation:

a

(6r + 7) + (13 + 7r) ( remove brackets and collect like terms )

= 6r + 7 + 13 + 7r

= 13r + 20

b

remove brackets and collect like terms

13 - r - 1 + r

= 12 - r

c

remove brackets and collect like terms

= - 8 - r + 2r - 4

= - 12 + r

d

remove brackets and collect like terms

= 7r - - - 6r

[-   - = - - = - ]

= r -