A bicycle tire has a diameter of 62 \text{ cm}62 cm62, start text, space, c, m, end text. What is the distance the bicycle tire travels in 101010 revolutions?

The distance bicycle tire travels is 1946.8 cm.

Step-by-step explanation:

Given:

Diameter of bicycle tire = 62 cm.

The bicycle tire travels in 10 revolutions.

Now, to find the distance the bicycle tire travels in 10 revolutions.

Diameter = 62 cm.

Radius (r) =

So, we get the circumference first by putting formula:

Thus, we get the circumference of tire 194.68 cm.

Number of revolutions the tire travels = 10.

Now, to get the distance the bicycle tire travels we multiply circumference of tire by number of revolutions the tire travels:

Therefore, the distance bicycle tire travels is 1946.8 cm.

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204