Find the vertical asymptote(s) of f (x) = StartFraction x squared minus 1 Over 2 x + 6 EndFraction.

We have the function:

The vertical asymptote can be found when the denominator equal zero, therefore:

So the vertical asymptote occur at

arithmetic sequence

step-by-step explanation:

given that a sequence has terms as

19, 15, 11,

this is represented on a graph

the pattern indicates that the sequence is an arithmetic sequence with i term

a=19 and common difference d =-4

any general term

thus the sequence is reduced by 4 for each successive term starting from 1 and nth term is

24-5n.

first negative term would start after 5th term

5th term =24-25< 0

from 5th term onwards the sequence would be negative.

this is a very good question

step-by-step explanation:

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