The temperature was very cold. Then the temperature doubled. Then the temperature dropped by 10 degrees. Then the temperature increased by 40 degrees. The temperature is now 16 degrees. What was the starting temperature?

The temperature was very cold.

The starting temperature is -7 degrees.

Given:

Changes in temperature

Final temperature = 16 degrees

Let the initial temperature be x

After the temperature is doubled =

After dropping by 10 degrees =

After increase by 40 degrees =

As per the question, the value of x can be calculated as,

degrees

Therefore, the starting temperature is -7 degrees.

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the starting temperature is - 7 degrees.

Step-by-step explanation:

Let x represent the starting temperature.

Then the temperature doubled. It means that it became 2x degrees

Then the temperature dropped by 10 degrees. It means that it became 2x - 10 degrees.

Then the temperature increased by 40 degrees. It means that it became 2x - 10 + 40 = 2x + 30 degrees.

If the temperature is now 16 degrees, it means that

2x + 30 = 16

2x = 16 - 30

2x = - 14

x = - 14/2

x = - 7 degrees

last option

step-by-step explanation:

given that δdef is right and isoceles,

assuming that side df is the hypotenuse means that de an ef are the other 2 sides that intersect at 90° and are of equal length.

because they are of equal length, we can say that they are congruent

because they intersect at 90°, their slopes must be opposite reciprocals.

only the last option satisfies these conditions.

c: lkllmn.

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