Zer - 25$ Soil- 6.25 Jamie is starting a garden. She buys 3 bags of potting soil and 4 bags of fertilizer. In all she spent 125$. After she used all of the soil and fertilizer, she realized that it wasn't enough for her garden. She goes back to the store and buys 4 more bags of potting soil and 2 more bags of fertilizer. She spent 75$ F represents fertilizer S represents soil 3s + 4f = 125 4s + 2f = 75

The price of fertilizer is $27.5  and potting soil is $5

Step-by-step explanation:

I think that you are asking for the price of each bag of fertilizer and potting soil. And here is my

Given the system of linear:

3s + 4f = 125  <=> f = 31.25 -3/4s (1)

4s + 2f = 75   <=> f = 37.5 -2s (2)

Take (1) -(2) we have:

f -f = 31.25 -3/4s - (37.5 -2s)

<=> 0 = -6.25 + 1.25s

<=> 1.25s  = 6.25

<=> s = 5

=> f = 37.5 -2(5) = 27.5

So the price of fertilizer is $27.5  and potting soil is $5

hello :

by applying the distributive property :

6 × 4.3 = 6 × ( 4 + 0.3 )

            =   (6 ×   4) + (6 ×   0.3)

            = 24 + 1.8

6 × 4.3 = 25.8

c = 0.429t

step-by-step explanation:

the constant rate at which carlos harvests cassava is 35 minutes per 15 cassavas 15/35 = 0.429 cassava per minute

therefore, an equation that models the number of cassava (c) that harvest carlos in a time (t) is the following:

where t is the time in minutes.

this means that when 35 minutes have elapsed 15 cassava have been harvested, at 70 minutes 30 cassava have been harvested and so on.