An article in Wear (1992, Vol. 152, pp. 171-181) presents data on the fretting wear of mild steel and oil viscosity. Representative data follow with x = oil viscosity and y = wear volume (10^(-4) cubic millimeters).
Round your answers to two decimal places (e. g. 98.76).

Engine MPG
Carline Displacement (in^3) (highway)
300C/SRT-8 215 30.8
CARAVAN 2WD 201 32.5
CROSSFIRE ROADSTER 196 35.4
DAKOTA PICKUP 2WD 226 28.1
DAKOTA PICKUP 4WD 226 24.4
DURANGO 2WD 348 24.1
GRAND CHEROKEE 2WD 226 28.5
GRAND CHEROKEE 4WD 348 24.2
LIBERTY/CHEROKEE 2WD 148 32.8
LIBERTY/ CHEROKEE 4WD 226 28
NEON/SRT 4/SX 2.0 122 41.3
PACIFICA 2WD 215 30.0
PACIFICA AWD 215 28.2
PT CRUISER 148 34.1
RAM 1500 PICKUP 2WD 500 18.7
RAM 1500 PICKUP 4WD 348 20.3
SEBRING 4-DR 165 35.1
STRATUS 4-DR 148 37.9
TOWN & COUNTRY 2WD 148 33.8
VIPER CONVERTIBLE 500 25.9
WRANGLER/TJ 4WD 148 26.4

y 240 181 193 155 172 110 113 75 94
x 1.6 9.4 15.5 20.0 22.0 35.5 43.0 40.5 33.0

(a) Construct a scatter plot of the data. Does a simple linear regression model appear to be plausible?
(b) Fit the simple linear regression model using least squares. Find an estimate of σ2.
(c) Predict fretting wear when viscosity x = 30.

.632

step-by-step explanation:

6 * 1/10 = 3/5

3*0.01 = 0.03

3/5 + 0.03 = .63

2*0.002 = .002

.63 + 0.002 = .632

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841

the diameter is 16 cm. are you a teacher?

step-by-step explanation:

second option

step-by-step explanation:

the measures of a triangle equal 180. use that to find x.

2x+3x+4x=180

9x=180

9x/9=180/9

x=20

now you know x, you know angle a is 40°, angle b is 60°, angle c is 80°.

because angle a is 40°, the first option doesn't work.

because angle b is 60°, the second option does work.

when you add angle a and b, you get 100°. complementary means it equals 90°, so the third option doesn't work.

when you add angle a and c, you get 120°, which is not 100.