The equation of line cd is y = 3x − 3. write an equation of a line perpendicular to line cd in slope-intercept form that contains point (3, 1).

Y = 3x - 3slope here is 3. A perpendicular line will contain a negative reciprocal slope. All that means is " flip " the slope and change the sign. So the slope we need is -1/3.

y = mx + b
slope(m) = -1/3
(3,1)x = 1 and y = 3
now we sub
3 = -1/3(1) + b
3 = -1/3 + b
3 + 1/3 = b
9/3 + 1/3 = b
10/3 = b

so ur perpendicular line is : y = -1/3x + 10/3