Can you help me find out what c is?

 "    " .

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Step-by-step explanation:

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The question states:  "Can [you] help [me] find out what "c" is ? " .

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       "Can [you] help [me] find out what "c" is ? " .

 →  We are to "Part C" —within the "attached image" given:

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 →   " ÷ " ;  can be written in the form of:  " " .

 →     Express z  in terms of m and n .

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Note: Rewrite:  " " ;   and:  " " ;   as powers of "" ;

  →  with "" being the "base number" .

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Let us start with:  " " .

Note that the number:  " " ;

     →   since " " ;  has 3 (three) zeros after the "1" digit;

     → & since:  " " .

So:  →   .

Now, let's simplify further.

Note the "multiplication property" of exponents:

    →   .

As such:  →  

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Likewise:  We can continue by rewriting our other term:

    →  " " ;  as a power of "" ;

             with "" being the "base number."

Note that the number:  " " ;

     →   since " " ;  has 2 (two) zeros after the "1" digit;

     →  & since:  " " .

So:

     →   .

Now, let's simplify further.

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Again:  As aforementioned:

Note the "multiplication property" of exponents:

    →   .

As such:

     →   .

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Now, refer to the original problem:

     →  "  ÷    "  ;  

Rewrite this expression by substituting:

    →   " " ;  ←  [for:  " ."] ;  And:

    →   " " ;   ←  [for:  " ."] ;

As follows:

    →  "  ÷   "  .

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Now:  Note the following "division property" of exponents:

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    →   ;  

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As such; let's rewrite our expression; and simplify—by plugging in our values into the "equation/formula" directly above; in which:

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→  " " [in the aforementioned formula] is:   " " .

→  " " [the 'exponent' in the aforementioned formula] is:                                                                                                    

                                                                          " " .

→  " " [the 'exponent' in the aforementioned formula is:

                                                                          " " .

→  " " [in the aforementioned formula] is:  " " ;

→  " "  [in the aforementioned formula] is:  " " .

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  →  Let's plug in our values;  and then "simplify" ; as follows:

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→   ? ;  

                .

→      .

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So:  →   " " ;

    ↔   " " .

         →  " " .

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Hope this answer is helpful.

  Best wishes to you in your academic endeavors

          —and within the "" community!

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answer:

total cost for tiles and paints is $924.  

step-by-step explanation:

we have been given that a community hall is in the shape of a cuboid. the hall is 40m long 15m high and 3m wide.

the paint will be required for 4 walls and ceiling.

let us find area of walls and ceiling.

therefore, the area of walls and ceiling is 1410 square meters.

given: cost for 10 litre of paint is $10 and 10 litre paint covers 25 square meter. therefore,

therefore, the total painting cost is $564.

tiles will be required for floor. let us find the area of floor.

given: 1m squared floor tiles costs $3. so,

therefore, the total tiles cost is $360.

now let us find combined total cost of tiles and paint.

therefore, the combined total cost of tiles and paint is $924.

an = 22 + (n-1) *6

110 seats

step-by-step explanation:

an=a1+(n-1)(d)

a1 = 22   this is the first item in the sequence

d =6   this is how the sequence goes up

a)   an = 22 + (n-1) *6

b) a12 = 22 + (12-1) *6

    a12 = 22+11*6

  a12 = 22 +88

  a12 = 110