An equation that passes through (0, -2/3) and (-3, -2/3)

y = 0x - 2/3

Step-by-step explanation:

We are asked to find the equation of the line

Step1: find the slope

( 0 , -2/3) ( 3 , -2/3)

m = (y_2 - y_1 )/ (x_2 - x_1)

x_1 = 0

y_1 = -2/3

x_2 = 3

y_2 = -2/3

Insert the values into the equation

m =( -2/3 - (-2/3) / (3 - 0)

= -2/3 + 2/3 / 3

= 0 / 3

m = 0

Step 2: sub m into the equation

y = mx + c

y = 0x + c

Step 3: sub any of the two points given into the eqn

y = 0x + c

Let's pick ( 3 , -2/3)

x = 3

y = -2/3

-2/3 = 0(3) + c

-2/3 = 0 + c

c = -2/3

Step4: sub c into the equation

y = mx + c

y = 0x + c

y = 0x - 2/3

Therefore, the equation of the line is

y = 0x - 2/3