A phone company offers two packages of service. Package A is $35.00 per month with an additional charge of $0.15 per minute for long distance. Package B is $45.00 per month with an additional charge of $0.10 per minute for long distance. How many minutes have to be used for the costs of both plans to be the same?

200 minutes have to be used for the costs of both plans to be the same.

Step-by-step explanation:

Let x represent the number of minutes that have to be used for the costs of both plans to be the same.

Package A is $35.00 per month with an additional charge of $0.15 per minute for long distance. This means that the cost of using package A for x minutes in a month would be

35 + 0.15x

Package B is $45.00 per month with an additional charge of $0.10 per minute for long distance. This means that the cost of using package A for x minutes in a month would be

45 + 0.1x

For both costs to be the same, it means that

35 + 0.15x = 45 + 0.1x

0.15x - 0.1x = 45 - 35

0.05x = 10

x = 10/0.05

x = 200

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

answer

106 emergencies

step-by-step explanation: