For the function y=-2x^2 + 4x +1, what are the coordinates of the vertex? Is it a maximum or minimum point? Consider using x = -b/2a. Show all work algebraically.

Vertex: is this a Minimum or Maximum?

The vertex is (1, 3). It's a max.

Step-by-step explanation:

I'm gonna use completing the square to solve for the vertex.

y = -2x² + 4x + 1     ,     dividing by -2

y = x² - 2x - 1/2

y = x² - 2x + 1 - 1 - 1/2

y = (x² - 2x + 1) +(- 1 - 1/2)

y = (x² - 1)² + (- 1.5)     ,     multiplying back in the -2 I divided earlier

y = -2(x² - 1)² + -2(- 1.5)

y = -2(x² - 1)² + 3

Equation is now in form of y = a(x² - h)² + k where the vertex is (h, k).

y = a(x² - h)² + k

y = -2(x² - 1)² + 3

So the vertex is (1, 3).

It's a max because y = -x². A negative x² will form a frowning face; the curve will point down forming a max point.

it is x=-4

step-by-step explanation:

answer 1 : option "c"

answer 2 : option "d"

answer 3 : option "b"

answer 4 : option "d"

answer 5 : option "b"

answer 6 : option "a"

answer 7 : option "c"

answer 8 : option "d"

answer 9 : option "c"

answer 10 : option "d"

answer 11 : option "c"

answer 12 option "b"

answer 13 option "c"

answer 14 option "c"

answer 15 option "d"

answer 16 option "a"

answer 17 option "b"

answer 18 option "c"

answer 19 option "a"

answer 20 option "a"

answer 21 option "c"

d