The endpoints of directed line segment PQ have coordinates of P(-7, -5) and Q(5,3). What are the coordinates of point A, on PQ, that divide PQ into a ratio of 1:3? *

The coordinates of point A on PQ that divides the line PQ in the ratio of 1:3 is (-4,-3)

The given information are:

Coordinates of P(-7, -5)

Coordinates of Q(5,3)

Where,

The formula to calculate the coordinates of point A is:

Therefore, the coordinates of point A are (-4,-3).

To know more about the calculation of the coordinates, refer to the link below:

link

Therefore the co-ordinate of the point A is (-4,-3)

Step-by-step explanation:

If A(x₁,y₁) and B(x₂,y₂)  is divided by a point in ration m:n internally.

Then the co-ordinate of the point is  .

Given two points are P(-7,-5) and Q(5,3).

A point A on PQ, that divides PQ into a ratio of 1:3.

Since the point A lies on the PQ.

Therefore it divides the line segment PQ internally.

Here x₁= -7,y₁= -5 ,  x₂= 5,y₂ =3, m=1,n=3

Therefore the co-ordinate of the point A is

=(-4,-3)

eve and marks ratios are equivalent

step-by-step explanation: