An airline knows from experience that the distribution of the number of suitcases that get lost each week on a certain route is approximately normal with μ = 15.5 and σ = 3.6. What is the probability that during a given week the airline will lose more than 20 suitcases?

0.1056

Step-by-step explanation:

z=(x-μ)/σ

as you know, μ=15.5 and σ=3.6

z=1.25

P(x > 20) = P( z > 20) = P(z > 1.25) = normalcdf(1.25 , 100) = 0.1056

let x be the money she spent so that she can earn the free t-shirt.

since, she already spent $112.49

⇒

also, as per the statement: jennifer must spend $250 or more in order to qualify for a free t-shirt at the store.

then,

we have an inequality i.,e

subtract 112.49 from both sides we get;

therefore, $137. 51 more money does jennifer need to spend so that she can earn the free t-shirt

2x^2+5x+17

your welcome. : )