A particular fruit's weights are normally distributed, with a mean of 738 grams and a standard deviation of 14 grams. The heaviest 2% of fruits weigh more than how many grams? Give your answer to the nearest gram.

We get that the heaviest of fruits weigh 766.84 grams.

Step-by-step explanation:

We know that a particular fruit's weights are normally distributed, with a mean of 738 grams and a standard deviation of 14 grams.

We have:

We calculate x:

We use the standard normal table and we get: Z=2.06.

So, we get

We get that the heaviest of fruits weigh 766.84 grams.

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3