The local supermarket buys lettuce each day to ensure really fresh produce. Each morning any lettuce that is left from the previous day is sold to a dealer that resells it to farmers who use it to feed their animals. This week the supermarket can buy fresh lettuce for $8.00 a box. The lettuce is sold for $16.00 a box and the dealer that sells old lettuce is willing to pay $1.80 a box. Past history says that tomorrow's demand for lettuce averages 245 boxes with a standard deviation of 38 boxes. How many boxes of lettuce should the supermarket purchase tomorrow

The supermarket should purchase 251 boxes of lettuce tomorrow.

Step-by-step explanation:

Let X = number of boxes of lettuce that the supermarket should purchase tomorrow

The information provided is:

Cost price per box = $8.00

Selling price per box = $16.00

The amount paid by the dealer for selling old lettuce per box (Salvage price) = $1.80

The mean number of boxes demanded for lettuce is, μ = 245.

The standard deviation of the number of boxes demanded for lettuce is, σ = 38.

Excess cost per box is,

Shortage cost per box is,

Compute the level of service as follows:

For the service level value the z-value is,

z = 0.1596

*Use a z-table.

Compute the value of x as follows:

Thus, the supermarket should purchase 251 boxes of lettuce tomorrow.

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

sinn is the total amount of students now and m were the students before, you subtract them both (n-m) and divide that by m. then, since to get a percentage from a fraction you have to multiply by 100, your answer should look like this: n-m/m*100

step-by-step explanation: