G A particular fruit's weights are normally distributed, with a mean of 738 grams and a standard deviation of 14 grams. The heaviest 2% of fruits weigh more than how many grams? Give your answer to the nearest gram.

The heaviest 2% of fruits weigh more than 767 grams.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean and standard deviation , the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

The heaviest 2% of fruits weigh more than how many grams?

More than X when Z has a pvalue of 0.98. So X when Z = 2.054.

Rounded to the nearest gram

The heaviest 2% of fruits weigh more than 767 grams.

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step-by-step explanation:

answer:

3 bags of apples and 2 bags of oranges.

step-by-step explanation: