The diameters of bolts produced in a machine shop are normally distributed with a mean of 6.46 millimeters and a standard deviation of 0.05 millimeters. Find the two diameters that separate the top 9% and the bottom 9%. These diameters could serve as limits used to identify which bolts should be rejected. Round your answer to the nearest hundredth, if necessary.

Step-by-step explanation:

Let X be the diameter of bolts produced in a machine shop

X is normal with mean = 6.46 mm and std dev = 0.05 mm.

We are to find the two diameters that separate the top 9% and the bottom 9%.

We can use std normal distribution value for this and from Z we can calculate X values

P(Z<z) = 0.09 and P(Z<z1) = 0.91

z=-1.341 and z1 = +1.341

Corresponding X values would be

for bottom 9%

X = 6.46-1.341*0.05 = 6.39295

X = 6.46+1.341*0.05=6.52305

google dat sis

step-by-step explanation:

24 units

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