Between 2005 -2009, the percent (in decimal form)of network commercials that lasted exactly 18 seconds could be modeled by the equation y=0.38x2-1.8\0.56x2+100,where x is the number of years since 2005 what percent of network commercials lasted exactly 18 seconds in 2008?Round you answer to the nearest percent

Approximately 1.54% of the commercials lasted exactly 18 seconds in 2008.

Step-by-step explanation:

We are given the following in the question:

y is the percent of network commercials that lasted exactly 18 seconds and x is the number of years since 2005.

We have to estimate the percentage of advertisement that  lasted exactly 18 seconds in 2008.

Thus, we put x = 3 in the equation:

Thus, approximately 1.54% of the commercials lasted exactly 18 seconds in 2008.

c is the correct answer

step-by-step explanation:

the figures below are made out of circles, semicircles, quarter … find the area and the perimeter of each figure and give your answers as a completely simplified exact value in terms of π (no approximations). remember that we'll also have to cut whatever areas we get in half, since we're only dealing

step-by-step explanation: