Write x^2 - 6x + 7= 0 in the form (x-a)^2 b, where a and b are intergers.
(x-4)^2=3
(x-3)^...
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Mathematics, 19.03.2020 18:17 wheeler2455
Write x^2 - 6x + 7= 0 in the form (x-a)^2 b, where a and b are intergers.
(x-4)^2=3
(x-3)^2=2
(x-2)^2=1
(x-1)^2=4
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Answers: 2
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