The dimensions of rectangle A are four times the dimensions of rectangle B. The area of rectangle B is 162 cm2. What is the area of rectangle A?

2,592 square cm.

Step-by-step explanation:

It is given that the dimensions of rectangle A are four times the dimensions of rectangle B.

Let dimensions of rectangle B are l×b.

So, the dimensions of rectangle A are 4l×4b.

Area of rectangle is

Area of rectangle B is

The area of rectangle B is 162 square cm.

Area of rectangle A is

Therefore, the area of rectangle A is 2,592 square cm.

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)

i pretty sure it is